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15 Permutations & Combinations Questions and Answers
15 solved Permutations & Combinations questions with step-by-step explanations. Includes formulas, shortcuts, and tips for placement tests and competitive exams.
Practice permutations & combinations questions with detailed explanations. These solved examples cover the most frequently asked patterns in placement and competitive exams.
Q1
Easy
Find 10P4.
Explanation:
nPr = n!/(n-r)! = 5040.
Q2
Easy
Find 10P3.
Explanation:
nPr = n!/(n-r)! = 720.
Q3
Easy
Find 8P4.
Explanation:
nPr = n!/(n-r)! = 1680.
Q4
Easy
How many distinct arrangements are possible for letters in 'MATH'?
Explanation:
All letters are distinct. Arrangements = 4! = 24.
Q5
Easy
Find 7P2.
Explanation:
nPr = n!/(n-r)! = 42.
Q6
Easy
Find 8P3.
Explanation:
nPr = n!/(n-r)! = 336.
Q7
Medium
Find 10P2.
Explanation:
nPr = n!/(n-r)! = 90.
Q8
Medium
How many distinct arrangements are possible for letters in 'CODE'?
Explanation:
All letters are distinct. Arrangements = 4! = 24.
Q9
Medium
How many ways can 5 members be chosen from 10 members?
Explanation:
Selection uses combination: 10C5 = 252.
Q10
Medium
How many distinct arrangements are possible for letters in 'QUIZ'?
Explanation:
All letters are distinct. Arrangements = 4! = 24.
Q11
Medium
How many ways can 3 members be chosen from 12 members?
Explanation:
Selection uses combination: 12C3 = 220.
Q12
Hard
Find 9P2.
Explanation:
nPr = n!/(n-r)! = 72.
Q13
Hard
How many ways can 2 members be chosen from 9 members?
Explanation:
Selection uses combination: 9C2 = 36.
Q14
Hard
How many distinct arrangements are possible for letters in 'BOOK'?
Explanation:
All letters are distinct. Arrangements = 4! = 24.
Q15
Hard
How many ways can 5 members be chosen from 6 members?
Explanation:
Selection uses combination: 6C5 = 6.
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